当S1,S2合上时,R3被短路,R1.R2并联
1/R并 = 1/R1+1/R2
R并 = U/I1 = 12 / 0.8 = 15
即1/15 = 1/R1 + 1/20 R1 = 60Ω
当S1,S2断开,R2,R3串联
R2 + R3 = U/ I2 = 12 / 0.2 = 60
R3 = 60 - 20 = 40Ω
如图电路中,电源电压为6V,R2=20欧.当S1,S2合上时,电流表示数为0.4安,当S1,S2断开时,电流表示数为0.1安.求R1和R3的值
如图电路中,电源电压为6V,R2=20欧.当S1,S2合上时,电流表示数为0.4安,当S1,S2断开时,电流表示数为0.1安.求R1和R3的值
物理人气：745 ℃时间：2020-04-11 21:37:46
优质解答
我来回答
类似推荐
猜你喜欢
- 1求二次函数y=x平方-3x与X轴的交点,写以下解题过程.谢谢您!
- 2汽车尾气对空气有什么污染
- 3they never sleep but sometimes they rest（ ）a short time.a.in b.for c.at
- 4My eating habits are very good
- 5英语翻译
- 6go home to tell me
- 7Which do you think is more important,to ask or to give?Why?请问如何用英语回答?
- 8设数列{an}的前n项和Sn=n2，则a8=_．
- 9at our school与in our school的区别
- 10讨论二次函数y=f（x）=ax²+bx+c（a≠0）在闭区间[p,q]上的最值情况.