根据下列条件求代数式2a分之-b+√b²-4ac的值 坐等
根据下列条件求代数式2a分之-b+√b²-4ac的值 坐等
(1)a=2,b=-8,c=5 (2)a=1,b=10,c=-15
(1)a=2,b=-8,c=5 (2)a=1,b=10,c=-15
数学人气:440 ℃时间:2019-12-18 18:32:46
优质解答
1、=8/(2×2)+√(64-4×2×5) =2+√ 24 =2+2√6 2、=-10/(2×1)+√[100-4×1×(-15)] =-5+√160 =-5+4√10 如果是:2a分之(-b+√b²-4ac) 1、=[8 +√(64-4×2×5)]/(2×2) =(8+√ 24)/4...
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