已知;如图,BE.CE分别为三角形ABC外角平分线,角CAF是角BAC的邻补角,那么你能说出角FAC与角E的关系吗证明

两角关系为：∠FAC=2∠E证明∵∠EBC=1/2(∠BAC+∠ACB)∠ECB=1/2(∠BAC+∠ABC)∴∠EBC+∠ECB+∠E=180°即：∠BAC+∠ABC/2+∠ACB/2+∠E=180°∠BAC=180°-∠ABC-∠ACB∴∠E=∠ABC/2+∠ACB/2∵∠FAC=∠ABC+∠ACB所以：...