函数y=2sin(兀x/6-兀/3)(0

因为 y=2sin(πx/6 -π/3)的周期为T=2π/(π/6)=12令2kπ-π/2 ≤πx/6 -π/3≤2kπ+π/2,解得 12k-1≤x≤12k+5,k是整数,从而 y在[0,5]是增函数,在[5,9]是减函数所以 当x=5时,y有最大值为2,当 x=0时,y有最小值为-√3...