已知函数f（x）=cos²x+根号3sinxcosx+1,x∈R

f(x)=cos²x+√3sinxcosx+1=(cos2x+1)/2+√3/2*sin2x+1=(√3/2*sin2x+1/2*cos2x)+3/2=sin(2x+π/6)+3/21,最小正周期T=2π/2=π最大值f(x)max=1+3/2=5/2最小值f(x)min=-1+3/2=1/22,令2kπ-π/2≤2x+π/6≤2kπ+π...