解方程组:x+2y+3z=62x+3y+z=63x+y+2z=6.
解方程组:
.
|
数学人气:413 ℃时间:2019-12-18 09:11:48
优质解答
x+2y+3z=6①2x+3y+z=6②3x+y+2z=6③,①+②+③得6x+6y+6z=18,所以x+y+z=3④,②-①得x+y-2z=0⑤,④-⑤得3z=3,解得z=1,③-①得2x-y-z=0⑥,④+⑥得3x=3,解得x=1,把x=1,z=1代入④得1+y+1=3,解得y=1,所以原...
我来回答
类似推荐
猜你喜欢
- 1描写树木的诗句
- 2已知|x-二分之一|+(y-2)²=0,求x的负一次方+y的负一次方?
- 3在平行四边形中ABCD中,向量AC=(1,2),向量 BD=(-3,2),求向量AD点乘向量AC
- 4计算 a的2005次方除a的401次方除以a的5次方=______________ (-a)除(-a)的平方除(-a)的立方
- 5As students,we__________ study very hard for our future.填must还是should?
- 61.I think I was at school ,___I was staying with a friend during the vacation when I heard the news.C
- 7“人们从书中可以感受快乐,感受生活,感受人生”这句话的理解.
- 8以must 开头的疑问句一般该怎样做
- 9二次函数与b^2-4ac有什么关系
- 10在进行多项式的乘法(x^2+mx+n)(x^2-3x+2)时,若结果中不含x^2项和x,求m与n的值