(1/sin10)-(√3/cos10)
(1/sin10)-(√3/cos10)
数学人气:964 ℃时间:2020-04-11 11:34:02
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1/sin10°)-(√3)/cos10° =(cos10°)-(√3)sin10°)/(sin10°×cos10°) =2(1/2 cos10°-(√3)/2 sin10°))/(sin10°×cos10° =2(sin30°cos10°-cos30°sin10°)/(sin10°×cos10°) =2sin20°/(sin10°×cos10°...
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