| sinx |
| cosx |
∴sinx=xcosx
同理，siny=ycosy
所以原式=
| sinxcosy+cosxsiny |
| x+y |
| sinxcosy−cosxsiny |
| x−y |
=
| xcosxcosy−ycosxcosy |
| x−y |
| xcosxcosy+ycosxcosy |
| x+y |
=
| cosxcosy(x+y) |
| x+y |
| cosxcosy(x−y) |
| x−y |
=cosxcosy-cosxcosy
=0
故答案为：0
实数x，y满足tanx=x，tany=y，且|x|≠|y|，则sin(x+y)x+y−sin(x−y)x−y=_．
实数x，y满足tanx=x，tany=y，且|x|≠|y|，则
−
=______．
| sin(x+y) |
| x+y |
| sin(x−y) |
| x−y |
数学人气：345 ℃时间：2020-03-18 20:42:47
优质解答
tanx=
=x
∴sinx=xcosx
同理，siny=ycosy
所以原式=
-
=
-
=
-
=cosxcosy-cosxcosy
=0
故答案为：0
∴sinx=xcosx
同理，siny=ycosy
所以原式=
=
=
=cosxcosy-cosxcosy
=0
故答案为：0
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