(1)设进价是x元,
则有:(1+60%)x=200,
解得:x=125.
故进价为125元.
(2)最低售价是125×(1+20%)=150元时,老板方可盈利,
故最低售价为150老板方可盈利.
据了解,个体服装销售要高出进价的20%出售方可盈利.一服装老板以高出进价的60%标价.如果一件服装标价200元,那么: (1)进价是多少元? (2)最低售价多少时,老板方可盈利?
据了解,个体服装销售要高出进价的20%出售方可盈利.一服装老板以高出进价的60%标价.如果一件服装标价200元,那么:
(1)进价是多少元?
(2)最低售价多少时,老板方可盈利?
(1)进价是多少元?
(2)最低售价多少时,老板方可盈利?
数学人气:360 ℃时间:2020-04-16 06:11:28
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