已知X1,X2是关于x的方程x²-2(m+2)x+2m²-1=0的两个实数根,且满足x1^2+x2^2=10,求m的值
已知X1,X2是关于x的方程x²-2(m+2)x+2m²-1=0的两个实数根,且满足x1^2+x2^2=10,求m的值
数学人气:575 ℃时间:2019-11-12 07:07:53
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X1,X2是关于x的方程x²-2(m+2)x+2m²-1=0的两个实数根,则有X1+X2=2(m+2)X1*X2=2m²-1所以x1^2+x2^2=10,即(x1+x2)^2-2x1*x2=[2(m+2)]^2-2(2m²-1)=4(m²+4m+4)-4m²+2=4m²+16m+16-4m...
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