将f(X)＝1/x²-5X+6展成（X＝1）的幂级数

1/(x²-5x+6)=1/[(x-2)(x-3)]=1/(x-3)-1/(x-2)=1/(2-x)-1/(3-x)=1/(1-(x-1))-1/(2-(x-1))=1/(1-(x-1))-(1/2)/(1-(x-1)/2)=Σ(x-1)^n-(1/2)Σ[(x-1)/2]^n n=0到+∞=Σ(x-1)^n-Σ(1/2^(n+1))(x-1)^n n=0到+∞=Σ(1...