①a2-ab=15,②ab-b2=-10
①+②得:a2-ab+(ab-b2)=a2-b2=15+(-10)=5.
已知a2-ab=15,ab-b2=-10,则代数式a2-b2=_.
已知a2-ab=15,ab-b2=-10,则代数式a2-b2=______.
数学人气:398 ℃时间:2019-10-09 11:43:04
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