x+2y+z=2-----(1) x-4y+z=5-----(2) 2x-2y-5z=0-----(3)
(1)*2+(2)得:3x+3z=9-----x+z=3-----(4) 并代入(1)或(2) 得:y=-1/2
代入(3)得:2x-5z=-1-----(5) (4)*5+(5)得:7x=14 ==> x=2
代入(4)得:z=1 ∴x=2,y=-1/2,z=1.
x+2y+z=2,x-4y+z=5,2x-2y-5z=0(三元一次方程组的解)
x+2y+z=2,x-4y+z=5,2x-2y-5z=0(三元一次方程组的解)
数学人气:921 ℃时间:2020-01-21 15:49:29
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