已知0≤x≤1. (1)若x-2y=6,则y的最小值是 _; (2)若x2+y2=3,xy=1,则x-y=_.
已知0≤x≤1.
(1)若x-2y=6,则y的最小值是 ______;
(2)若x2+y2=3,xy=1,则x-y=______.
(1)若x-2y=6,则y的最小值是 ______;
(2)若x2+y2=3,xy=1,则x-y=______.
数学人气:737 ℃时间:2019-10-02 22:15:44
优质解答
(1)∵x-2y=6,∴y=x2-3,∵12>0,∴此函数为增函数,故x=0时,y有最小值,y最小=-3.(2)∵0≤x≤1,xy=1,∴x、y互为倒数,∵x2+y2=3,xy=1,∴(x-y)2=x2+y2-2xy=3-2=1,∴x-y=±1,∵x、y互为倒数,∴x-y=x-...
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