(2x-3)(3x-2)-6(x-1)(x+1)
=6x^ - 13x +6 - 6(x^-1)
=6x^ - 13x +6 - 6x^ + 6
= - 13x +12
代入 x = 1/13
= -13× 1/13 + 12
= -1 + 12
= 11
(2x-3)(3x-2)-6(x-1)(x+1)其中x=13分之1
(2x-3)(3x-2)-6(x-1)(x+1)其中x=13分之1
数学人气:506 ℃时间:2020-02-03 21:20:37
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