当k取何值时,分式方程6/(x-1)=(x+k)/「x(x-1)」-3/x有解?

6/(x-1)=(x+k)/「x(x-1)」-3/x6x=(x+k)-3(x-1)6x=-2x+(k+3)k=8x-3因为x≠0,x≠1当x=0时,k=8*0-3=-3当x=1时,k=8*1-3=5所以,k≠-3,k≠5即:k≠-3且k≠5时,分式方程6/(x-1)=(x+k)/「x(x-1)」-3/x都有解:(k+3)/8...