△ABC的三边满足a⁴+b²c²-a²c²-b⁴=0,试判定△ABC的形状
△ABC的三边满足a⁴+b²c²-a²c²-b⁴=0,试判定△ABC的形状
数学人气：434 ℃时间：2019-12-06 04:45:50
优质解答
a⁴+b²c²-a²c²-b⁴=0→（a²-b²）*（a²+b²）+c²（b²-a²）=0→（a²-b²）*（a²+b²-c²）=0应该是等腰三角形或直角三角形.
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