(1/4-1/(2π))x=2(π - 2)
(1-2/π)x=8(π-2)
(π-2)x=8π(π-2)
x=8π
4X=2π*[X-2(π - 2)]
2x=π*[x-2π+4]
2x-πx=-2π(π-2)
(2-π)x=-2π(π-2)
-x=-2π
x=2π
怎么解这两个一元一次方程【有答案,
怎么解这两个一元一次方程【有答案,
(1/4-1/(2π))x=2(π - 2),
x=8π
4X=2π*[X-2(π - 2)]
得X=2π
(1/4-1/(2π))x=2(π - 2),
x=8π
4X=2π*[X-2(π - 2)]
得X=2π
其他人气:936 ℃时间:2019-08-22 19:35:30
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