a/(x-a) +b =1
a/(x-a)-(b-1)=0
{ a - (b-1)(x-a) } / (x-a) = 0
{ (b-1)x +ab } / (x-a) = 0
(b-1)x +ab = 0
x = ab/(1-b)(x-a分之a )+b=1是这个题目a/(x-a) +b =1a/(x-a)-(b-1)=0{ a - (b-1)(x-a) } / (x-a) = 0{- (b-1)x +ab } / (x-a) = 0x≠a-(b-1)x +ab = 0x = ab/(b-1) ,且x≠a
解方程求X :x-a分之a+b=1(b≠1)
解方程求X :x-a分之a+b=1(b≠1)
(x-a分之a )+b=1是这个题目
(x-a分之a )+b=1是这个题目
数学人气:279 ℃时间:2020-05-19 04:48:24
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