∵多项式a2+(2k-6)ab+b2+9不含ab的项,
∴2k-6=0,
解得k=3.
故答案为:3.
在a2+(2k-6)ab+b2+9中,不含ab项,则k=_.
在a2+(2k-6)ab+b2+9中,不含ab项,则k=______.
数学人气:926 ℃时间:2020-05-12 20:13:47
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