过抛物线y^2=4x的焦点作倾斜角为π/3的弦AB,求AB

由y^2=2px=4x (1)得2p=4,p=2.抛物线的焦点F(p/2,0) ---->F(1,0)过焦点F且倾斜角为π/3的直线的方程为：y=k(x-1)=tan(π/3)(x-1).故 y=√3(x-1).(2)(1)、(2)式,得：x1=3,x2=1/3.y1=2√3.y2=-2√3/3.即,A(3,2√3),B(1/...