已知-3≤log以1/2为底x的对数≤-1/2,求函数y=(log2为底 x/2的对数)(log2为底 x/4的对数)的值域

log(1/2)(8)=-3≤log(1/2)(x)≤-1/2=log(1/2)(√2)∴8≥x≥√2y=[log(2)(x/2)][log(2)(x/4)]=[log(2)(x) -1][log(2)(x) -2]令log(2)(x)=t∈[1/2,3]∴y=(t-1)(t-2)=t²-3t+2函数图象对称轴t=3/2,开口向上,则f(t)m...