4a-1/(a+1)(a-1)=m/(a+2)+n/(a-1),则m+n=
4a-1/(a+1)(a-1)=m/(a+2)+n/(a-1),则m+n=
数学人气：680 ℃时间：2020-04-16 10:20:52
优质解答
因为4a-1/(a+2)(a-1)=m/(a+2) + n/(a-1),且m/(a+2) + n/(a-1)=m(a-1)+n(a+2)/(a+2)(a-1) 所以4a-1/(a+2)(a-1)=m(a-1)+n(a+2)/(a+2)(a-1) 所以4a-1=m(a-1)+n(a+2) =ma-m+na+2n =a(m+n)-(m-2n) 所以4=m+n 1=m-2n m=4-n...
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