f(x)=2√3sinxcosx +2cos²x-1
=√3sin2x+ 1+ cos2x-1
==√3sin2x+cos2x
=2sin(2x+π/6)
最小正周期=π
x【0,π/2】 2x+π/6【π/6,7π/6】
最大值为2 最小值为0
2kπ+π/2
已知函数f(x)=2√3sinxcosx 2cos²x-1(x∈R)
已知函数f(x)=2√3sinxcosx 2cos²x-1(x∈R)
(1)求函数f(x)的最小正周期及在区间【0,π/2】上的最大值和最小值.
(2)求函数的单调减区间
(1)求函数f(x)的最小正周期及在区间【0,π/2】上的最大值和最小值.
(2)求函数的单调减区间
数学人气:692 ℃时间:2019-10-11 12:50:38
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