a+b=4
ab=1
a=2＋根号3 b=2-根号3
或
a=2－根号3 b=2＋根号3
那么a平方＋b平方＝14＝c平方
因此此三角形为直角三角形
已知△ABC的3边分别为abc,且a+b=4,ab=1,c=根号14,试判断△ABC的形状
已知△ABC的3边分别为abc,且a+b=4,ab=1,c=根号14,试判断△ABC的形状
数学人气：726 ℃时间：2019-10-19 19:47:45
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