a=1/3
b=1
所以
3a²-2ab+1
=3×（1/3）²-2×3×1/3+1
=1/3-2+1
= -2/3
已知a为3的倒数,b为最小的正整数,则代数式3a²-2ab+1的值是
已知a为3的倒数,b为最小的正整数,则代数式3a²-2ab+1的值是
数学人气：980 ℃时间：2020-01-25 03:38:14
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