∵Eξ=3,Dξ=1,
∴E[3(ξ-1)]=3Eξ-3
=3×3-3=6.
故选:D.
设离散型随机变量ξ满足Eξ=3,Dξ=1,则E[3(ξ-1)]等于( ) A.27 B.24 C.9 D.6
设离散型随机变量ξ满足Eξ=3,Dξ=1,则E[3(ξ-1)]等于( )
A. 27
B. 24
C. 9
D. 6
A. 27
B. 24
C. 9
D. 6
数学人气:874 ℃时间:2020-01-28 00:36:16
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