计算:①-5(a²-2)-2(3a²+5) ②-2(ab-3a²)-[2b²-(5ab+a²)+2ab]
计算:①-5(a²-2)-2(3a²+5) ②-2(ab-3a²)-[2b²-(5ab+a²)+2ab]
数学人气:777 ℃时间:2020-02-04 11:21:48
优质解答
解-5(a²-2)-2(3a²+5)=(-5a²-6a²)+(10-10)=-11a²-2(ab-3a²)-[2b²-(5ab+a²)+2ab]=-2ab+6a²-(2b²-5ab-a²+2ab)=-2ab+6a²-(2b²-a²-3ab)=(-2ab+3a...
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