f(x)=sin³xcosx+cos³xsinx+√3sin²x
=sinxcosx(sin²x+cos²x)+√3(1-cos2x)/2
=sin2x/2+√3(1-cos2x)/2
=sin(2x+60°)+√3/2
T=π 值域为-1+√3/2到1+√3/2
f(x)=sin³xcosx+cos³xsinx+√3sin²x,求最小正周期和值域
f(x)=sin³xcosx+cos³xsinx+√3sin²x,求最小正周期和值域
数学人气:817 ℃时间:2020-10-01 05:26:06
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