是函数有意义,则同时满足1-x^2>=0,x^2-1>=0
解得x=1
定义域为{1}
函数f(x)=根号下1-x的平方+根号下x的平方-1的定义域为
函数f(x)=根号下1-x的平方+根号下x的平方-1的定义域为
数学人气:384 ℃时间:2019-08-21 10:13:31
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