f(3x)=log2√2/9x+1 则f(1)的值为

解 f(3x)=log2√2/9x+1
=log2√2/3x*3+1
f(1)=log2√2/3+1
=2/3log2/2^2
=4/3
错了是f(3x)=log2√9x+1/2
=log2(√(3*3x+1)/2
f(x)=log2(√(3x+1)/2
f(1)=log2(√(3+1)/2)
=log2(2)
=1