已知直线y=kx+b平行于直线y=-3x+4,且与直线y=2x-6的交点在x轴上.求这个一次函数的解析式
已知直线y=kx+b平行于直线y=-3x+4,且与直线y=2x-6的交点在x轴上.求这个一次函数的解析式
数学人气:944 ℃时间:2019-10-19 22:02:27
优质解答
因为直线y=kx+b平行于直线y=-3x+4,可得到k=-3又因为y=kx+b与直线y=2x-6的交点在x轴,所以将y=0代入y=2x-6中,解得x=3,将k=-3和x=3代入y=kx+b中,解得b=9.所以次一次函数解析式为y=-3x+9
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