原式=lg15/lg2
=[lg(3×5)]/a
=(lg3+lg5)/a
=[b+(1-lg2)]/a
=(b-a+1)/a
已知lg2=a,lg3=b,试用a,b表示log2 15
已知lg2=a,lg3=b,试用a,b表示log2 15
数学人气:397 ℃时间:2020-03-28 19:28:41
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