若 log以a为底x的对数=2,log以b为底x的对数=3,log以c为底x的对数=6,则log以abc为底x的对数的值是多少?

由loga(b)=1/logb(a)
又loga(x)=2,logb(x)=3,logc(x)=6,
∴logx(a)=1/2,logx(b)=1/3,logx(c)=1/6
logabc(x)
=1/logx(abc)
=1/[logx(a)+logx(b)+logx(c)]
=1/(1/2+1/3+1/6)
=1