已知x,y是实数,且x²+y²-4x-6y+12=0求x²+y²的最值和x-y的最值
已知x,y是实数,且x²+y²-4x-6y+12=0求x²+y²的最值和x-y的最值
数学人气:306 ℃时间:2019-10-26 23:23:00
优质解答
(1)x²+y²-4x-6y+12=0配方:(x-2)²+(y-3)²=1点P(x,y)的轨迹为圆,其中圆心C(2,3),半径r=1|OC|=√(3²+2²)=√13∵√(x²+y²)=|PO|∴x²+y²=|PO|²而|PO|max=|PC...
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