f(-x)=ax^2+bcosx-sinx-1
f(x)=ax^2+bcosx+sinx-1
f(x)-f(-x)=2sinx
f(π/6)-f(-π/6)=2sin(π/6)=1
f(-π/6)=4
已知f(x)=ax^2+bcosx+sinx-1满足f(π/6)=5,则f(-π/6）等于多少
已知f(x)=ax^2+bcosx+sinx-1满足f(π/6)=5,则f(-π/6）等于多少
数学人气：296 ℃时间：2020-07-09 10:07:44
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