已知函数f(x)=根号下3倍的sinxcosx+(cosx)^2

答：
f(x)=√3sinxcosx+(cosx)^2
=(√3/2)*2sinxcosx+(1/2)*[2(cosx)^2-1]+1/2
=(√3/2)sin2x+(1/2)cos2x+1/2
=sin(2x+π/6)+1/2
1）f(x)的最小正周期T=2π/2=π
2）-π/6