在三角形ABC中,a^2+b^2=1999c^2,则,cotC/cotA+cotB的值为?
在三角形ABC中,a^2+b^2=1999c^2,则,cotC/cotA+cotB的值为?
cotA+cotB都在 分母上
cotA+cotB都在 分母上
数学人气:733 ℃时间:2019-11-03 19:34:12
优质解答
cotC/cotA+cotB=(cosC/sinC)/[(cosA/sinA)+(cosB/sinB)]=[(cosC·sinA·sinB)/sinC]/(sinA·cosB+cosA·sinB)=(cosC·sinA·sinB)/[sinC·sin(A+B)]=(cosC·sinA·sinB)/[sinC·sin(π-C)]=(cosC·sinA·sinB)/(sinC...
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