3=√9>√8
√7>√5,则-√7若a,b为实数，且a=√2b－14＋√7－b＋3，求√﹙a＋b﹚²的值a=√(2b－14)＋√(7－b)＋3所以2b-14≥0,7-b≥0从而b=7 代入上式得a=3故√﹙a＋b﹚²=√10²=10
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