函数f(x)的定义域为D={x|x不等于零},且满足对于任意x1,x2∈D,有f(x1x2)=f(x1)+f(x2);

1) 令x1 = x2 = 1;带入f(x1x2)=f(x1)+f(x2);
f(1) = f(1) + f(1)===> f(1) = 0;
2) 令x1 = x2 = -1;带入f(x1x2)=f(x1)+f(x2);
0 = f(1) = f(-1) + f(-1)===> f(-1) = 0;
令x1 = -1;带入f(x1x2)=f(x1)+f(x2);
f(-x2) = f(-1) + f(x2)===> f(-x2) = f(x2);===> f(x)是偶函数
3) f(4*4) = f(4) + f(4) = 2
f(4*4*4) = f(4*4)+f(4)=2+1=3
所以 f(64) = 3 , f(x)是偶函数,所以,f(-64) = 3
f(3x+1)+f(2x-6) = f( (3x + 1)(2x - 6))