已知x^2-7x+1=0,求x^4+1/x^4的值
已知x^2-7x+1=0,求x^4+1/x^4的值
很急很急 快啊!
很急很急 快啊!
其他人气:969 ℃时间:2020-02-05 06:11:23
优质解答
2207有过程没啊?因为x不等于0,由题干消去X得x+1/x=7,则两边平方的(x+1/x)^2=49,得x^2+1/x^2=47,然后两边平方得(x^2+1/x^2)=x^4+1/x^4+2,最后得出x^4+1/x^4=47^2-2=2207
我来回答
类似推荐
猜你喜欢
- 1某商品原来利润率为10%,由于进价便宜了20%,售价不变的情况下,该商品的利润率增加到(x+10)%,则x=
- 2Would he like some tea?还是Would he like any tea?
- 39999×7778+3333×6666.
- 4how many ways can people travel from shanghai to beijing in the passage是什么意思
- 5Fell like I gonna Dream every time
- 6My sister Shirly and I 1 very different.She's 2 ,but I'm short.She 3 short curly dark hair,
- 75分钟等于多少小时怎么算
- 8英语作文 When I grow up
- 95x+35.5=90怎么写方程?还有:6x+34=22乘4 有:4x-3.5乘0.5=6.25 有:16+4.5x=25 2.4x/12=4.8 这些都怎么
- 1030篇初一英语作文带翻译 50词