∵{1,2}⊆A⊆{1,2,3,4,5},∴集合A中必须含有1,2两个元素,
因此满足条件的集合A为{1,2},{1,2,3},{1,2,4},{1,2,5},{1,2,3,4},{1,2,3,5},{1,2,4,5},{1,2,3,4,5}共8个.
故选C.
若{1,2}⊆A⊆{1,2,3,4,5}}则满足条件的集合A的个数是( ) A.6 B.7 C.8 D.9
若{1,2}⊆A⊆{1,2,3,4,5}}则满足条件的集合A的个数是( )
A. 6
B. 7
C. 8
D. 9
A. 6
B. 7
C. 8
D. 9
数学人气:819 ℃时间:2020-04-15 18:06:19
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