sin2π/5+cos26π/5+2cos3π*sin5π/6
=sin2π/5+cos(5π+π/5)+2cos(2π+π)*sin(π-π/6)
=sin2π/5-cosπ/5-2sinπ/6
=2sinπ/5cosπ/5-cosπ/5-1
=2×0.6×0.8-0.8-1
=-0.84
sin2π/5+cos26π/5+2cos3π*sin5π/6=?
sin2π/5+cos26π/5+2cos3π*sin5π/6=?
数学人气：892 ℃时间：2020-05-27 19:19:14
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