解
原式
=(5x²-x²)+(-x-5x)+(2-3)
=4x²-6x-1
原式
=(2x²-x²)+(-3x+3x)+(1-5)
=x²-4
原式
=(4a-5a)+(6b-2b)+(3c+4c)
=-a+4b+7c
原式
=(x³-x³)+(-3x²y+3x²y)+(3xy²+3xy²)+y³
=6xy²+y³
原式
=(2a²+4a²)+(3a-4a)+(-1/2-2
=6a²-a-5/2
原式
=(3/2x²-3/4x²)+(-2x+3/2x)+(-1+3/4)
=3/4x²-1/2x-1/4
计算:(1)(5x²+2-x)+(-x²-5x-3);(2)(2x²-3x+1)-(5-3x+x²);
计算:(1)(5x²+2-x)+(-x²-5x-3);(2)(2x²-3x+1)-(5-3x+x²);
(3)(4a+6b+3c)+(4c-2b-5a);
(4)(x³-3x²y+3xy²)-(x³-3x²y-3xy²-y³)
(5)(2a²-½+3a)-4(a-a²+½);(6)½(3x²-4x-2)-¾(x²-2x-1)
这是整式的运算的题!
(3)(4a+6b+3c)+(4c-2b-5a);
(4)(x³-3x²y+3xy²)-(x³-3x²y-3xy²-y³)
(5)(2a²-½+3a)-4(a-a²+½);(6)½(3x²-4x-2)-¾(x²-2x-1)
这是整式的运算的题!
数学人气:900 ℃时间:2019-10-17 13:52:51
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