一个底面直径为5分米的圆柱,若平行于它的底面截去一个高3分米的圆柱后,剩下圆柱的侧面积展开后正好是一个正方形,求原圆柱的侧面积
一个底面直径为5分米的圆柱,若平行于它的底面截去一个高3分米的圆柱后,剩下圆柱的侧面积展开后正好是一个正方形,求原圆柱的侧面积
数学人气：622 ℃时间：2019-10-23 03:56:23
优质解答
底面直径5分米,则周表为5*3．14=15．6分米,即截3分米后高15．6分米.则原高15.6+3=18.6分米.原侧面积18.6*15.6=290平方分米
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