原式=x(x2+3x-2)+2x2+6x+18
=x(x2+3x-2)+2(x2+3x-2)+22
∵x2+3x-2=0,
∴原式=22.
故答案为22.
若x2+3x-2=0,则x3+5x2+4x+18=_.
若x2+3x-2=0,则x3+5x2+4x+18=______.
数学人气:974 ℃时间:2020-01-26 04:05:57
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