ab=1,
1/(a²+1)+1/(b²+1)
=(b²+1)/(a²+1)(b²+1)+(a²+1)/(b²+1)(a²+1)
=(a²+1+1+b²+1)/(a²+1)(b²+1)
=(a²+2+b²)/(a²b²+a²+b²+1)
=(a²+2+b²)/(1+a²+b²+1)
=1
已知实数a,b满足ab=1,求1/(a²+1)+1/(b²+1)的值
已知实数a,b满足ab=1,求1/(a²+1)+1/(b²+1)的值
数学人气:336 ℃时间:2020-03-23 15:23:13
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