0.1mol/L的 (NH4)2SO4溶液
NH4的浓度近似为0.2mol/L
SO4为0.1mol/L
H离子为水解产物 浓度最少
所以c(NH4+)>c(SO4-)>c(H+)
0.1mol/l的硫酸铵溶液中微粒浓度关系为c(NH4+)>c(SO4-)>c(H+),为什么对
0.1mol/l的硫酸铵溶液中微粒浓度关系为c(NH4+)>c(SO4-)>c(H+),为什么对
化学人气:867 ℃时间:2019-12-01 13:12:56
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