已知过抛物线y^2=2px(p>0)的焦点 斜率为2根号2的直线交抛物线于A(x1,y1),B(x2,y2) -(x1

焦点(p/2,0)设直线AB:y=2√2(x-p/2)代入y²=2px得4x²-5px+p²=0x1+x2=5p/4|AB|=x1+x2+p=9p/4=9p=4即抛物线y²=8xA(1,-2√2),B(4,4√2)(2)设C(x,y)OC=OA+λOB(x,y)=(1,-2√2)+λ(4,4√2)(x,y)=(4λ+...