解方程：5x+3（9-x）=41 5x+10(25-x）=170 2x+4(10-x)=32 急 要求,
解方程：5x+3（9-x）=41 5x+10(25-x）=170 2x+4(10-x)=32 急 要求,
数学人气：937 ℃时间：2020-02-13 20:53:35
优质解答
5x+3（9-x）=41 5x+27-3x=412x+27=412x=41-272x=14x=14/2x=75x+10(25-x）=170 5x+250-10x=170250-170=10x-5x80=5xx=80/5x=162x+4(10-x)=32 2x+40-4x=32 40-32=4x-2x8=2xx=8/2x=4
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